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§ 58.137 拒绝接收的生?Excluded milk)

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放大字体缩小字体2011-07-11 08:31:45 来源:GPO 浏览次数9span id="hits">3253
核心提示:生乳在以下情况下,生产企业不准接收:生乳沉淀物含量处于No. 3水平十天以上;连续五个生乳样品中有三个样品菌落总数超过500000CFU/mL;连续五个牛奶样品中有三个样品体细胞数超?50000?mL;药物残留检验为阳性、/div>
发布单位
FDA
FDA
发布文号 67 FR 48975
发布日期 2002-07-29 生效日期 暂无
有效性状?/th> 废止日期 暂无
备注 生乳在以下情况下,生产企业不准接收:生乳沉淀物含量处于No. 3水平十天以上;连续五个生乳样品中有三个样品菌落总数超过500000CFU/mL;连续五个牛奶样品中有三个样品体细胞数超?50000?mL;药物残留检验为阳性、/td>

   58.137 Excluded milk.

  A plant shall not accept milk from a producer if:

  (a The milk has been in a probational (No. 3 sediment content classification for more than 10 calendar days?sect;58.134);

  (b Three of the last five milk samples have exceeded the maximum bacterial estimate of 500,000 per ml.?sect;58.135(c)(3))、/p>

  (c Three of the last five milk samples have exceeded the maximum somatic cell count level of 750,000 per ml. ?,000,000 per ml. for goat milk?sect;58.133(b)(6)) or

  (d The producer's milk shipments to either the Grade A or the manufacturing grade milk market currently are not permitted due to a positive drug residue test?sect;58.133(c)(4))、/p>

  [58 FR 26913, May 6, 1993, as amended at 67 FR 48975, July 29, 2002]

  更多关于美国生乳质量管理规范,请详见美国生乳质量管理规范汇怺/a>

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